[kicad-users] How do I create this footprint?

[David Gravereaux [e-mail] [kicad-users]]

Hi,

I'm having trouble creating a footprint for this part:
http://www.knowles.com/eng/content/download/5786/93110/version/3/file/SPH0641LM4H-1.pdf

See page 9 (land pattern) and also the stencil


How do I make a ring with an outer diameter of 1.625mm and an inside
diameter of 1.025mm?

How do I create the different paste stencil pattern, too?

[[e-mail] [kicad-users]]

pad 3 needs to be a ring

['John Woodgate' [e-mail] [kicad-users]]

I'm not an expert at all, but three decimal places of millimetres is probably beyond any PCB maker that doesn't supply the military at $$$$.

However, I think someone may have converted inches to millimetres with mind not engaged. 1.625 mm is 0.064 inch and 1.024 mm is 0.040 inch.

With best wishes DESIGN IT IN! OOO – Own Opinions Only
www.jmwa.demon.co.uk J M Woodgate and Associates Rayleigh England

Sylvae in aeternum manent.

-----Original Message-----
From: kicad-***@yahoogroups.com [mailto:kicad-***@yahoogroups.com]
Sent: 25 July 2017 19:33
To: kicad-***@yahoogroups.com
Subject: [kicad-users] How do I create this footprint?

Hi,

I'm having trouble creating a footprint for this part:
http://www.knowles.com/eng/content/download/5786/93110/version/3/file/SPH0641LM4H-1.pdf

See page 9 (land pattern) and also the stencil


How do I make a ring with an outer diameter of 1.625mm and an inside diameter of 1.025mm?

How do I create the different paste stencil pattern, too?

[David Gravereaux [e-mail] [kicad-users]]

Not on ultralibrarian, either

https://app.ultralibrarian.com/Detail/Item?octoId=973d5d12e60d48fa&tab=m

[[e-mail] [kicad-users]]

sorry, bad link https://app.ultralibrarian.com/ECAD/search?queryText=SPH0641LM4H-1 https://app.ultralibrarian.com/ECAD/search?queryText=SPH0641LM4H-1

[David Gravereaux [e-mail] [kicad-users]]

Post by 'John Woodgate' ***@btinternet.com [kicad-users]
I'm not an expert at all, but three decimal places of millimetres is probably beyond any PCB maker that doesn't supply the military at $$$$.
However, I think someone may have converted inches to millimetres with mind not engaged. 1.625 mm is 0.064 inch and 1.024 mm is 0.040 inch.

It's correct. Yes, this small.

I need a RING shape to specify inner and outer diameters. I tried to
look-up the .kicad_mod file format, but can't find the info. Pad 3 is
the problem.

(module SPH0644LM4H-1 (layer F.Cu) (tedit 59778CDD)
(fp_text reference REF** (at 0 2.94) (layer F.SilkS)
(effects (font (size 1 1) (thickness 0.15)))
)
(fp_text value SPH0644LM4H-1 (at 0.04 -2.74) (layer F.Fab)
(effects (font (size 1 1) (thickness 0.15)))
)
(fp_line (start -1.325 -1.75) (end 1.325 -1.75) (layer F.CrtYd) (width
0.15))
(fp_line (start 1.325 -1.75) (end 1.325 1.75) (layer F.CrtYd) (width
0.15))
(fp_line (start 1.325 1.75) (end -1.325 1.75) (layer F.CrtYd) (width
0.15))
(fp_line (start -1.325 -1.75) (end -1.325 1.75) (layer F.CrtYd) (width
0.15))
(fp_line (start -1.325 -1.75) (end 1.325 -1.75) (layer F.SilkS) (width
0.15))
(fp_line (start 1.325 -1.75) (end 1.325 1.75) (layer F.SilkS) (width
0.15))
(fp_line (start 1.325 1.75) (end -1.325 1.75) (layer F.SilkS) (width
0.15))
(fp_line (start -1.325 1.75) (end -1.325 -1.75) (layer F.SilkS) (width
0.15))
(pad 1 smd rect (at -0.82 -1.34) (size 0.725 0.522) (layers F.Cu
F.Paste F.Mask))
(pad 2 smd rect (at -0.82 -0.54) (size 0.725 0.522) (layers F.Cu
F.Paste F.Mask))
(pad 5 smd rect (at 0.82 -1.34) (size 0.725 0.522) (layers F.Cu
F.Paste F.Mask))
(pad 4 smd rect (at 0.81 -0.54) (size 0.725 0.522) (layers F.Cu
F.Paste F.Mask))
(pad 3 smd circle (at 0 0.72) (size 1.625 1.625) (layers F.Cu F.Paste
F.Mask))
(pad "" np_thru_hole circle (at 0 0.71) (size 0.5 0.5) (drill 0.5)
(layers *.Cu *.Mask))
)

[[e-mail] [kicad-users]]

It's correct. Yes, this small.

I need a RING shape to specify inner and outer diameters. I tried to
look-up the .kicad_mod file format, but can't find the info. Pad 3 is
the problem.

(module SPH0644LM4H-1 (layer F.Cu) (tedit 59778CDD)
(fp_text reference REF** (at 0 2.94) (layer F.SilkS)
(effects (font (size 1 1) (thickness 0.15)))
)
(fp_text value SPH0644LM4H-1 (at 0.04 -2.74) (layer F.Fab)
(effects (font (size 1 1) (thickness 0.15)))
)
(fp_line (start -1.325 -1.75) (end 1.325 -1.75) (layer F.CrtYd) (width 0.15))
(fp_line (start 1.325 -1.75) (end 1.325 1.75) (layer F.CrtYd) (width 0.15))
(fp_line (start 1.325 1.75) (end -1.325 1.75) (layer F.CrtYd) (width 0.15))
(fp_line (start -1.325 -1.75) (end -1.325 1.75) (layer F.CrtYd) (width 0.15))
(fp_line (start -1.325 -1.75) (end 1.325 -1.75) (layer F.SilkS) (width 0.15))
(fp_line (start 1.325 -1.75) (end 1.325 1.75) (layer F.SilkS) (width 0.15))
(fp_line (start 1.325 1.75) (end -1.325 1.75) (layer F.SilkS) (width 0.15))
(fp_line (start -1.325 1.75) (end -1.325 -1.75) (layer F.SilkS) (width 0.15))
(pad 1 smd rect (at -0.82 -1.34) (size 0.725 0.522) (layers F.Cu F.Paste F.Mask))
(pad 2 smd rect (at -0.82 -0.54) (size 0.725 0.522) (layers F.Cu F.Paste F.Mask))
(pad 5 smd rect (at 0.82 -1.34) (size 0.725 0.522) (layers F.Cu F.Paste F.Mask))
(pad 4 smd rect (at 0.81 -0.54) (size 0.725 0.522) (layers F.Cu F.Paste F.Mask))
(pad 3 smd circle (at 0 0.72) (size 1.625 1.625) (layers F.Cu F.Paste F.Mask))
(pad "" np_thru_hole circle (at 0 0.71) (size 0.5 0.5) (drill 0.5) (layers *.Cu *.Mask))
)

[Andy Eskelson [e-mail] [kicad-users]]

High res numerical values were on the the things introduced into kicad
some time ago. It enables kicad to connect things up exactly even if
mixed measurements / mixed devices are used. i.e. metric / imperial.

It's nothing to worry about generally as it's all done automatically in
most cases.

Andy



On Tue, 25 Jul 2017 20:04:30 +0100

Post by 'John Woodgate' ***@btinternet.com [kicad-users]
I'm not an expert at all, but three decimal places of millimetres is probably beyond any PCB maker that doesn't supply the military at $$$$.
However, I think someone may have converted inches to millimetres with mind not engaged. 1.625 mm is 0.064 inch and 1.024 mm is 0.040 inch.
With best wishes DESIGN IT IN! OOO – Own Opinions Only
www.jmwa.demon.co.uk J M Woodgate and Associates Rayleigh England
Sylvae in aeternum manent.
-----Original Message-----
Sent: 25 July 2017 19:33
Subject: [kicad-users] How do I create this footprint?
Hi,
http://www.knowles.com/eng/content/download/5786/93110/version/3/file/SPH0641LM4H-1.pdf
See page 9 (land pattern) and also the stencil
How do I make a ring with an outer diameter of 1.625mm and an inside diameter of 1.025mm?
How do I create the different paste stencil pattern, too?
------------------------------------
------------------------------------
Please read the Kicad FAQ in the group files section before posting your question.
Please post your bug reports here. They will be picked up by the creator of Kicad.
Please visit http://www.kicadlib.org for details of how to contribute your symbols/modules to the kicad library.
For building Kicad from source and other development questions visit the kicad-devel group at http://groups.yahoo.com/group/kicad-devel
------------------------------------
Yahoo Groups Links

[Andy Eskelson [e-mail] [kicad-users]]

If the footprint can have a hole in that pad then just use a normal
through hold pad

set the pad diameter to the outside dia to 1.625 and the drill size to
1.025

Set clearances to zero.

If you cannot have a hole then I think you can manually remove that
particular pad from the drill file, but take advice on that.


Andy



On Tue, 25 Jul 2017 11:33:29 -0700

Post by David Gravereaux ***@pobox.com [kicad-users]
Hi,
http://www.knowles.com/eng/content/download/5786/93110/version/3/file/SPH0641LM4H-1.pdf
See page 9 (land pattern) and also the stencil
How do I make a ring with an outer diameter of 1.625mm and an inside
diameter of 1.025mm?
How do I create the different paste stencil pattern, too?

[David Gravereaux [e-mail] [kicad-users]]

Post by Andy Eskelson ***@g0poy.co.uk [kicad-users]
If the footprint can have a hole in that pad then just use a normal
through hold pad
set the pad diameter to the outside dia to 1.625 and the drill size to
1.025
Set clearances to zero.
If you cannot have a hole then I think you can manually remove that
particular pad from the drill file, but take advice on that.
Andy

Thanks Andy. The drill hole needs to be somewhere around 0.5mm, known
as 'aperture size' for this microphone.

Manually editing the drill size might work, but only if the pad is
properly drawn as a ring.

I will experiment

[[e-mail] [kicad-users]]

Nope. Doesn't work. A filled ring is what I need